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va_arg
Syntax:
#include <stdarg.h> type va_arg( va_list argptr, type ); void va_end( va_list argptr ); void va_start( va_list argptr, last_parm ); The va_arg() macros are used to pass a variable number of arguments to a function.
For example:
int sum( int num, ... ) {
int answer = 0;
va_list argptr;
va_start( argptr, num );
for( ; num > 0; num-- ) {
answer += va_arg( argptr, int );
}
va_end( argptr );
return( answer );
}
int main( void ) {
int answer = sum( 4, 4, 3, 2, 1 );
printf( "The answer is %d\n", answer );
return( 0 );
}
This code displays 10, which is 4+3+2+1. Here is another example of variable argument function, which is a simple printing function:
void my_printf( char *format, ... ) {
va_list argptr;
va_start( argptr, format );
while( *format != '\0' ) {
// string
if( *format == 's' ) {
char* s = va_arg( argptr, char * );
printf( "Printing a string: %s\n", s );
}
// character
else if( *format == 'c' ) {
char c = (char) va_arg( argptr, int );
printf( "Printing a character: %c\n", c );
break;
}
// integer
else if( *format == 'd' ) {
int d = va_arg( argptr, int );
printf( "Printing an integer: %d\n", d );
}
*format++;
}
va_end( argptr );
}
int main( void ) {
my_printf( "sdc", "This is a string", 29, 'X' );
return( 0 );
}
This code displays the following output when run: Printing a string: This is a string Printing an integer: 29 Printing a character: X |